fossilesque@mander.xyzM to Science Memes@mander.xyzEnglish · 5 months agoI just cited myself.mander.xyzimagemessage-square12fedilinkarrow-up14arrow-down10
arrow-up14arrow-down1imageI just cited myself.mander.xyzfossilesque@mander.xyzM to Science Memes@mander.xyzEnglish · 5 months agomessage-square12fedilink
minus-squareValthorn@feddit.nulinkfedilinkEnglisharrow-up2·edit-25 months agox=.9999… 10x=9.9999… Subtract x from both sides 9x=9 x=1 There it is, folks.
minus-squarebarsoap@lemm.eelinkfedilinkEnglisharrow-up1·edit-25 months agoSomehow I have the feeling that this is not going to convince people who think that 0.9999… /= 1, but only make them madder. Personally I like to point to the difference, or rather non-difference, between 0.333… and ⅓, then ask them what multiplying each by 3 is.
minus-squareBuglefingers@lemmy.worldlinkfedilinkEnglisharrow-up1·2 months agoThe thing is 0.333… And 1/3 represent the same thing. Base 10 struggles to represent the thirds in decimal form. You get other decimal issues like this in other base formats too (I think, if I remember correctly. Lol)
minus-squareDeanFogg@lemm.eelinkfedilinkEnglisharrow-up0arrow-down1·5 months agoCut a banana into thirds and you lose material from cutting it hence .9999
minus-squarewholookshere@lemmy.blahaj.zonelinkfedilinkEnglisharrow-up1·5 months agoThat’s not how fractions and math work though.
minus-squareyetAnotherUser@discuss.tchncs.delinkfedilinkEnglisharrow-up1·edit-25 months agoUnfortunately not an ideal proof. It makes certain assumptions: That a number 0.999… exists and is well-defined That multiplication and subtraction for this number work as expected Similarly, I could prove that the number which consists of infinite 9’s to the left of the decimal separator is equal to -1: ...999.0 = x ...990.0 = 10x Calculate x - 10x: x - 10x = ...999.0 - ...990.0 -9x = 9 x = -1 And while this is true for 10-adic numbers, it is certainly not true for the real numbers.
minus-squareColeSloth@discuss.tchncs.delinkfedilinkEnglisharrow-up0·5 months agoX=.5555… 10x=5.5555… Subtract x from both sides. 9x=5 X=1 .5555 must equal 1. There it isn’t. Because that math is bullshit.
minus-squareblue@ttrpg.networklinkfedilinkEnglisharrow-up1·5 months agox = 5/9 is not 9/9. 5/9 = .55555… You’re proving that 0.555… equals 5/9 (which it does), not that it equals 1 (which it doesn’t). It’s absolutely not the same result as x = 0.999… as you claim.
x=.9999…
10x=9.9999…
Subtract x from both sides
9x=9
x=1
There it is, folks.
Somehow I have the feeling that this is not going to convince people who think that 0.9999… /= 1, but only make them madder.
Personally I like to point to the difference, or rather non-difference, between 0.333… and ⅓, then ask them what multiplying each by 3 is.
The thing is 0.333… And 1/3 represent the same thing. Base 10 struggles to represent the thirds in decimal form. You get other decimal issues like this in other base formats too
(I think, if I remember correctly. Lol)
Cut a banana into thirds and you lose material from cutting it hence .9999
That’s not how fractions and math work though.
Unfortunately not an ideal proof.
It makes certain assumptions:
Similarly, I could prove that the number which consists of infinite 9’s to the left of the decimal separator is equal to -1:
...999.0 = x ...990.0 = 10x Calculate x - 10x: x - 10x = ...999.0 - ...990.0 -9x = 9 x = -1And while this is true for 10-adic numbers, it is certainly not true for the real numbers.
X=.5555…
10x=5.5555…
Subtract x from both sides.
9x=5
X=1 .5555 must equal 1.
There it isn’t. Because that math is bullshit.
x = 5/9 is not 9/9. 5/9 = .55555…
You’re proving that 0.555… equals 5/9 (which it does), not that it equals 1 (which it doesn’t).
It’s absolutely not the same result as x = 0.999… as you claim.