• expr@piefed.social
    link
    fedilink
    English
    arrow-up
    3
    arrow-down
    1
    ·
    2 months ago

    I assume it’s not just about the gravity, but also the much larger radius of the planet would mean much larger distance from the surface, and thus much more fuel needed.

    • degenerate_neutron_matter@fedia.io
      link
      fedilink
      arrow-up
      1
      ·
      2 months ago

      You’re sort of right. The change in distance from the surface is insignificant, but a spacecraft orbiting a bigger planet has to travel further with each orbit so its speed must be faster to avoid falling out of orbit, even if the gravitational acceleration at its orbital height is the same.

    • potatopotato@sh.itjust.works
      link
      fedilink
      English
      arrow-up
      0
      ·
      2 months ago

      That’s not how…what???

      F = G * (m1 * m2) / r^2

      Note that radius is both squared and the dividing term. More distance = less gravity

        • Lojcs@piefed.social
          link
          fedilink
          English
          arrow-up
          0
          ·
          2 months ago

          Wikipedia says energy = GMm/r.

          if g=GM/r² then energy = mgr, proportional to r given g is constant.

          apologies

          My previous comment was wrong, I derivated while integrating.

      • expr@piefed.social
        link
        fedilink
        English
        arrow-up
        1
        ·
        2 months ago

        I stated an assumption and was contributing to the conversation. Even if that assumption is incorrect, there’s no need to be a dick about it.

        It seems like a larger atmosphere would result in a longer duration exposed to atmospheric drag, thus requiring more fuel to overcome it.